> NOTE: This site is the official version of 2048. You can play it on your phone via http://git.io/2048. All other apps or sites are derivatives or fakes, and should be used with caution.
I though I would see this sooner. This might be barely solvable, but the next power( after 4096 ) is almost impossible to reach and there should be some innovation in gameplay.
I mean no negativity here, but isn't it neat how this is sorta like Call of Duty 5 or whatever sequel they're on now? Where people use terms like "milking the franchise."
Clearly, these forks/derivate works have some value (both to creators, and those playing), but I find the parallel to be interesting.
4096 = 2^12. So you would need to utilize at least 12 out of 16 squares (if done perfectly) in order to beat it.
Since there are 16 squares total it is not hard to put upped limit on highest possible variation of the game that you can actually beat at 2^15 = 32768. Unless somebody expands the field of course.
Actually, the smaller number that appears is 2, and if you are lucky the last two numbers you get are 4. The smaller number must be repeated to start the massive collapse. So the greatest winnable version is 4+4+8+16+...+65536 = 131072 = 2^17.
You are correct good sir, in the analysis above I eliminated luck whatsoever and set all numbers appearing to 2 make an argument. My analysis still holds with that restriction.
I've seen numbers as large as 128 appearing, so if we go that route greatest winnable version would be even higher. I suspect that maximum number appearing is based on max number on the board now, so while we are speculating, it could be possible to make endless game by dynamically adjusting window of appearing numbers.
// Adds a tile in a random position
GameManager.prototype.addRandomTile = function () {
if (this.grid.cellsAvailable()) {
var value = Math.random() < 0.9 ? 2 : 4;
var tile = new Tile(this.grid.randomAvailableCell(), value);
this.grid.insertTile(tile);
}
};
Might be good of you to remove that bit.