Are you in standard or scientific? Each new operator (Not sure if thats the correct term) is calculated immediately. ie 1+2x3 is worked out as 1+2 (Stored into buffer as 3) x 3 = 9
But scientific does it correctly where it just appends the new expression onto the buffer instead of applying it
But scientific does it correctly where it just appends the new expression onto the buffer instead of applying it